A nucleus moving with velocity `bar(v)` emits an `alpha`-particle. Let the velocities of the `alpha`-particle and the remaining nucleus be `bar(v)_(1)` and `bar(v)_(2)` and their masses be `m_(1)` and `(m_2)` then,A. `underset (v) rarr , underset (v_(1))rarr and underset (v_(2))rarr` must be parallel to each otherB. none of the two of `underset (v) rarr , underset (v_(1))rarr and underset (v_(2))rarr` should be paralle to each otherC. ` underset (v_(1))rarr + underset (v_(2))rarr` must be parallel to `underset (v) rarr `.D. ` m_(1) underset (v_(1)) rarr + m_(2)underset (v_(2)) rarr ` must be parallel to `underset (v) rarr`

A nucleus moving with velocity `bar(v)` emits an `alpha`-particle. Let

1.	A nucleus moving with velocity `bar(v)` emits an `alpha`-particle. Let the velocities of the `alpha`-particle and the remaining nucleus be `bar(v)_(1)` and `bar(v)_(2)` and their masses be `m_(1)` and `(m_2)` then,A. `underset (v) rarr , underset (v_(1))rarr and underset (v_(2))rarr` must be parallel to each otherB. none of the two of `underset (v) rarr , underset (v_(1))rarr and underset (v_(2))rarr` should be paralle to each otherC. ` underset (v_(1))rarr + underset (v_(2))rarr` must be parallel to `underset (v) rarr `.D. ` m_(1) underset (v_(1)) rarr + m_(2)underset (v_(2)) rarr ` must be parallel to `underset (v) rarr`
Answer» Correct Answer - d Since no external force is present, so momnetum conservation principle is completely appllicable `:. M because m vecv =vec m_(1)vecv_(1)+m_(2) vecv_(2)` or `(m_(1) +m_(2) vecv)=m_(1)vecv_(1)+m_(2)vecv_(2)`.

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