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A neutron breaks into a proton and electorn. Calculate the eenrgy produced in this reaction in `m_(e) = 9 xx 10^(-31) kg, m_(p) = 1.6725 xx 10^(-27) kg, m_(n) = 1.6747 xx 10^(-27) kg, c = 3xx10^(8)m//sec`. |
Answer» `._0^(1)nrarr_(1)^(1)p+ ._(-1)^(0)e` Mass defect: `Deltam = [1.6747 xx 10^(-27) - 1.3725 xx 10^(-27)-9xx10^(-31)]` `= 1.3 xx 10^(-30) kg` Energy produced `= Deltamc^(2) = 1.3 xx 10^(-30) xx (3xx10^(8))^(2)` `= 11.7xx10^(-14) J = (11.7 xx 10^(-14))/(1.6xx10^(-13)) = 0.73 MeV` |
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