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A sample has `4 xx 10^16` radioactive nuclei of half-life `10` days. The number of atoms decaying in `30` days is.A. `3.9 x 10^16`B. `5 xx 10^15`C. `10^16`D. `3.5 xx 10^16` |
Answer» Correct Answer - D (d) `N = 4 xx 10^16 ((1)/(2))^((30)/(10)) = (1)/(2) xx 10^16` Atoms decayed `= 4 xx 10^16 - (1)/(2) xx 10^16` =`3.5 xx 10^16`. |
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