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The binding energy per nucleon number for deutron `H_(1)^(2)`and helium ` He_(2)^(4)` are `1.1 MeV` and `7.0 MeV` respectively . The energy released when two deuterons fase to form a belium nucleus `He_(2)^(4)` is ……..A. `2.2MeV`B. `23.6MeV`C. `28.0MeV`D. `30.2MeV` |
Answer» Correct Answer - B `._(1)H^(2) +._(1)H^(2)rarr _(2)He^(4)` Energy `= 4xx7 - 4xx1.1 = 23.6MeV` |
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