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A number which divided by a divisor leaves a remainder of 27. Twice the number divided by the same divisor leaves the remainder of 3. Find the divisor. Please try to upload a picture of the answer. ​

Answer»

tion:Let Q1 be quotient of first DIVISION and q2 be the quotient of second division, d be the divisor and let original number be num.The 2 equations formed are:1) num=d*q1+272)2*num=d*q2+3Multiplying equation-1 by 2 and equating the equations GIVES us=>d*q2+3=2dq1+54Shifting the d term on one side and numbers on the other=>d*q2-2*q1=51Taking d common from the left side=>d(q2-2q1)=51=>d=51/q2-2*q1So d can either be 51 or one of its FACTOR(17 or 3)Since we have a reminder of 27 in one case d cannot be less than 27So divisor is 51



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