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A parallel plate air capacitor has capcity `C` distance of separtion between plates is `d` and potential difference `V` is applied between the plates force of attraction between the plates of the parallel plate air capacitor isA. `(C^(2)V^(2))/(2d^(2))`B. `(C^(2)V^(2))/(2d)`C. `(CV^(2))/(2d)`D. `(CV^(2))/(d)` |
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Answer» Correct Answer - C `F = (Q^(2))/(2 epsilon_(0)A)` `:. Q = CV` and `C = (epsilon_(0)A)/(d) rArr epsilon_(A) = Cd` So `F = (C^(2)V^(2))/(2Cd) = (CV^(2))/(2d)` |
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