A parallel plate capacitor has a plate area of 100 cm^2 and is separated by a distance of 20 mm. Find its capacitance.(a) 6.425 × 10^-12 F(b) 5.425 × 10^-12 F(c) 4.425 × 10^-12 F(d) 3.425 × 10^-12 FI had been asked this question during an online exam.I need to ask this question from Parallel Plate Capacitor topic in section Electrostatic Potential and Capacitance of Physics – Class 12

A parallel plate capacitor has a plate area of 100 cm^2 and is separat

1.	A parallel plate capacitor has a plate area of 100 cm^2 and is separated by a distance of 20 mm. Find its capacitance.(a) 6.425 × 10^-12 F(b) 5.425 × 10^-12 F(c) 4.425 × 10^-12 F(d) 3.425 × 10^-12 FI had been asked this question during an online exam.I need to ask this question from Parallel Plate Capacitor topic in section Electrostatic Potential and Capacitance of Physics – Class 12
Answer» Correct choice is (c) 4.425 × 10^-12 F To explain I would say: C = \(\frac {Q}{V} = [ \frac {\sigma A}{(\frac {\sigma d}{\varepsilon_0})} ] = \frac {A\varepsilon_0}{d}\). C = \(\frac {100 \times 10^{-4} \times 8.85 \times 10^{-12})}{(20 \times 10^{-3})}\) C = 4.425 × 10^-12 F.

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