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In a parallel plate capacitor, the capacitance increases from 100 F to 800 F, on introducing a dielectric medium between the plates. What is the dielectric constant of the medium?(a) 0.125(b) 125(c) 80(d) 8This question was addressed to me in a national level competition.My question is from Effect of Dielectric on Capacitance topic in portion Electrostatic Potential and Capacitance of Physics – Class 12

Answer»

The CORRECT OPTION is (d) 8

Easy explanation: Capacitance with dielectric = 800 F

Capacitance without dielectric = 100 F

Dielectric constant = \( ( \FRAC {Capacitance \, with \, dielectric}{Capacitance \, without \, dielectric} ) \)

k = \(( \frac {800 F}{100 F} )\)

k = 8.

Therefore, the dielectric constant is calculated as 8.



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