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Find out the correct expression of the capacitance of a parallel plate capacitor where ‘A’ is the area of the plates, ‘d’ is the distance between the plates and ‘ε0’is the permittivity of the medium.(a) \(\frac {A\varepsilon_0}{d}\)(b) \(\frac {Ad}{\varepsilon_0}\)(c) \(\frac {d\varepsilon_0}{A}\)(d) Aε0dI got this question in semester exam.My question is based upon Parallel Plate Capacitor in chapter Electrostatic Potential and Capacitance of Physics – Class 12

Answer»

Right answer is (a) \(\frac {A\varepsilon_0}{d}\)

Easy explanation: The capacitance of a PARALLEL PLATE CAPACITOR is directly proportional to the area of the plates and permittivity of the MEDIUM between the plates. It is indirectly proportional to the DISTANCE between the plates.

C = \(\frac {Q}{V} = [ \frac {\sigma A}{(\frac {\sigma d}{\varepsilon_0})} ] = \frac {A\varepsilon_0}{d}\).



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