1.

A part of the locus of a point P, which is equidstant from two intersecting line as + by + c = 0 and px + qy + r = 0

Answer»

`(a - p) x + (b - q) y + (c - x) = 0`
`AP + qby + cy = 0`
`sqrt(a^(2) + b^(2)) (px + QY + r) - sqrt(p^(2) + q^(2)) (ax + by + a)`
None of these

Solution :(i) Perpendicular distance of a point `P(x_(1), y_(1))` from the LINE, `px + qy + r = 0` is
`(|px_(1) + qy_(1) + r|)/(sqrt(p^(2) + q^(2)))`,
(ii) PERPENDICUALR distance of the point `(x_(1), y_(1))` to the line `ax + by + c = 0` is
`(|ax_(1) + qy_(1) + c|)/(sqrt(a^(2) + b^(2)))`,


Discussion

No Comment Found