Construct a DeltaABC whose perimeter is 10.5 cm and the base angles ar – InterviewSolution

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1.	Construct a DeltaABC whose perimeter is 10.5 cm and the base angles are 60^(@) and 45^(@).
Answer» Solution :Steps of CONSTRUCTION : 1. Draw `PQ = 10.5 cm.` 2. Construct `ANGLERPQ = 60^(@)` and `angleSQP = 45^(@)`. 3.Draw the bisector of `angleRPQ` and `angleSPQ` which intersect each other at`A.` 4. Join `AP` and `AQ.` 5. Draw the PERPENDICULAR bisectors of `AP` and `AQ` which intersect `PQ`at points `B` and `C` respectively. 6. Join `AB` and `AC.` `therefore DeltaABC` is the required triangle.

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