InterviewSolution
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InterviewSolution
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A particle executes SHM of amplitude a. (i) At whatdistance from the mean position is its kinetic energyequal to potential energy?(ii) At what points is its speedhalf the maximum speed?Ans. (i(ii)a-a |
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Answer» Potential energy = (1/2) kx^2=(1/2) mω^2x^2Kinetic energy = (1/2) mv^2= (1/2) m[ω√(A^2-x^2)]^2=(1/2) mω^2(A^2-x^2)Where,xis the required position about the mean position,A is amplitude of SHM,m is mass of particle executing SHM,ω is the angular frequency of the particle. Given, P.E. = K.E.so, (1/2) mω^2x^2 = (1/2) mω^2(A^2-x^2)so, x^2= A^2/2so,x =A/√2 I knew it I want 2nd part |
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