A particle has an initial velocity `(6hati+8hatj) ms^(-1)` and an acce – InterviewSolution

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1.	A particle has an initial velocity `(6hati+8hatj) ms^(-1)` and an acceleration of `(0.8hati+0.6hatj)ms^(-2)`. Its speed after 10s is
Answer» Velcocity of particle after `10s vecv=(6hati+8hatj)+10(3hati+4hatj)=36hati+48hatj` speed `=sqrt((36)^(2)+(48)^(2))=+sqrt(6^(2)+8^(2))=60ms^(-1)`

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