1.

A particle is dropped from height h.It strikesat ground after 5 s. What is value of h? (Giveng=10 ms-2)​

Answer»

Answer:

EXPLANATION:

FIRST body INITIAL speed u=0

Final speed =3m/s

Second body initial speed=4m/s

Body is dropped from height H

So a=g=10m/s  

2

 

V  

2

=u  

2

+2gh

3  

2

=0+20h  

9=20h

h=  

20

9

​  

 

Second object is also dropped from same height.

therefore, h=  

9

20

​  

 

u=4m/s

v  

2

=u  

2

+2gh

v=5m/s


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