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A particle is fired with velocity `u` making angle `theta` with the horizontal.What is the change in velocity when it is at the highest point?A. `u cos theta`B. uniform retardationC. `u sin theta`D. `(u cos theta-u)` |
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Answer» Correct Answer - C `Deltavecv=vecv_("top")-vecv_(1)` `(u cos theta)hati-[(u cos theta)hati+(u sin theta)hatj]=-(u sin theta) hatj` `|Deltavecv|=u sin theta` change in speed `=(u cos theta)-v` |
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