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A particle is fired with velocity `u` making angle `theta` with the horizontal.What is the change in velocity when it is at the highest point?A. `u cos theta`B. uniform retardationC. `u sin theta`D. `(u cos theta-u)`

Answer» Correct Answer - C
`Deltavecv=vecv_("top")-vecv_(1)`
`(u cos theta)hati-[(u cos theta)hati+(u sin theta)hatj]=-(u sin theta) hatj`
`|Deltavecv|=u sin theta`
change in speed `=(u cos theta)-v`


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