A particle is moving in X-Y plane under the actionof a force F such th

1.	A particle is moving in X-Y plane under the actionof a force F such that at some instant 't' thecomponents of its linear momentum p are p, 2cos t and p, 2 sin t. At this instant the anglebetween and F and p is(A) 90°(C) 180°(B) 0°(D) 30°
Answer» P(x) = 2 cos(t), F(x) = dP(x)/dt = -2 sin(t) P(y) = 2 sin (t), F(y) = dP(y)/dt = 2 cos (t) Dot product of momentum and Force = F(x)P(x) + F(y)P(y) = -4 sin(t)cos(t) + 4 sin(t)cos(t) = 0 Since dot product is zero, angle between the two is 90 degrees

A particle is moving in X-Y plane under the actionof a force F such that at some instant 't' thecomponents of its linear momentum p are p, 2cos t and p, 2 sin t. At this instant the anglebetween and F and p is(A) 90°(C) 180°(B) 0°(D) 30°

Answer»

P(x) = 2 cos(t), F(x) = dP(x)/dt = -2 sin(t)

P(y) = 2 sin (t), F(y) = dP(y)/dt = 2 cos (t)

Dot product of momentum and Force = F(x)*P(x) + F(y)*P(y) = -4 sin(t)cos(t) + 4 sin(t)cos(t) = 0

Since dot product is zero, angle between the two is 90 degrees

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A particle is moving in X-Y plane under the actionof a force F such that at some instant 't' thecomponents of its linear momentum p are p, 2cos t and p, 2 sin t. At this instant the anglebetween and F and p is(A) 90°(C) 180°(B) 0°(D) 30°

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