InterviewSolution
Saved Bookmarks
| 1. |
A particle is moving such that the velocity is given by `v=sqrt(2gammas)`, where `gamma` is constant and s is diplacement. Find the acceleration. |
|
Answer» `v=sqrt(2lambdas)=sqrt(2lambda)s^(1//2)` `(dv)/(ds)=sqrt(2lambda)1/2.s^(-1//2)=1/2sqrt((2lambda)/s)` `a=v(dv)/(ds)=sqrt(2lambda) s^(1//2).1/2sqrt((2lambda)/s)=lambda` |
|