Saved Bookmarks
| 1. |
A particle is performing uniform circular motion with velocity 40m/s. If the angle between the two velocity vector is 60° What will be the change in velocity? |
|
Answer» Δv = 2 v{θ/2} = 2 ×40 sin30 = 80 sin 30 = 80 ×1/2 = 40 m/s please MARK me brain mark list |
|