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A particle is placed at the origin and a force F=Kx is acting on it (where k is a positive constant). If `U_((0))=0`, the graph of `U (x)` verses x will be (where U is the potential energy function.)A. B. C. D. |
Answer» Correct Answer - A `F=-(dU)/(dx)=kx` or `U_((x))=int_(0)^(x)-kxdx=-(1)/(2)kx^(2)` Which is the equation of a parabola symmetrical to - y axis. |
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