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    				| 1. | A particle is projected at an angle of elevation `alpha` and after t second it appears to have an elevation of `beta` as seen from the point of projection. Find the initial velocity of projection. | 
| Answer» Correct Answer - A::B::C Let v is the velocity at time t Using `v_y = u_y + a_yt ` `:. v sin beta = usin alpha - g t` ………(i) `v_x = u_x` `:. v cos beta = u cos alpha …..(ii)` From Eqs. (i) and (ii), we get `((ucosalpha)/(cos beta)) sin beta = u sinalpha -g t` On solving we get, `u = (g t cosbeta)/(sin (alpha-beta))`. | |