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A particle is projected from a horizontal plane (x-zplane) such that its velocity vector at time t is givenby V-ai -(b- ct). Its range on the horizontalplane is given byba2ba(A)C(B) C(C) 3ba(C) c(D) |
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Answer» V=a i^+(b-ct)j^ Vx=Ux+axta=Ux+0Ux=a x=Uxt+0x=at----------------(1) Vy=Uy+aytb-ct=Uy-gtUy=b and g=cnow,y=Uyt+1/2ayt^2 0 =bt-1/2ct^22b-ct=0t=2b/c-----------(2)put (2)in equation (1)x=a2b/c=2ab/chence option (b) is correct |
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