A particle is projected with velocity u at an angle theta with the horizontal at t=0.What is the magnitude of change in thevelocity of the particle when it is atmaximum height

A particle is projected with velocity u at an angle theta with the h

1.	A particle is projected with velocity u at an angle theta with the horizontal at t=0.What is the magnitude of change in thevelocity of the particle when it is atmaximum height
Answer» At the TIME of PROJECTION, the particle's speed is u and the particle's speed at the HIGHEST POINT the particle's speed is ucosθ. So, the change in speed is,Δu=u−ucosθNow, the initial velocity is,u =ucosθ i^ +usinθ j^ and the final velocity (at highest point) is,v =ucosθ i^ Therefore, the change in velocity is,Δ v = u − v =ucosθ i^ +usinθ j^ −ucosθ i^ =usinθ j^ ⇒∣Δ v ∣=usinθ

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A particle is projected with velocity u at an angle theta with the horizontal at t=0.What is the magnitude of change in thevelocity of the particle when it is atmaximum height​

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A particle is projected with velocity u at an angle theta with the horizontal at t=0.What is the magnitude of change in thevelocity of the particle when it is atmaximum height