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A particle is released from a height h. At acertain height, its KE it two times its potentialenergy. Height and speed of the particle at thatinstant areh gh3"V3(3)2h 2gh(4) 2gh

Answer»

Total mechanical energy at hieght=k.e +p.e=mgh(as v=0)total mechanical enegy at hieght at the point=k.e+p.e=k.e+5/2k.e=7/2k.eby law of conservation of energymgh=7/2k.e2*mgh=2*7/2k.emgh=7*1/2mv^2gh=7/2v^22gh/7=v^2square root (velocity at height/7)=vH/3, 2√gH/3 is the ans to ur question



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