1.

A particle is thrown vertically upward from the ground with some velocity and it strikes the ground again in time 2 s. The maximum height achieved by the particle is : `(g=10 m//s^(2))`A. 2.50 mB. 1.25 mC. 6.25 mD. 5 m

Answer» Correct Answer - D
`A` to `B`, then `B` to `A`, time`=2 s`
`A` to `B`, time`=1 s`
`0=u-gxx1impliesu=10 m//s`
`0=u^(2)-2gHimpliesH=u^(2)/(2g)=5 m`


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