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A particle is thrown vertically upward from the ground with some velocity and it strikes the ground again in time 2 s. The maximum height achieved by the particle is : `(g=10 m//s^(2))`A. 2.50 mB. 1.25 mC. 6.25 mD. 5 m |
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Answer» Correct Answer - D `A` to `B`, then `B` to `A`, time`=2 s` `A` to `B`, time`=1 s` `0=u-gxx1impliesu=10 m//s` `0=u^(2)-2gHimpliesH=u^(2)/(2g)=5 m` |
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