A particle is thrown with initial speed u at angle ‘θ’, with the

1.	A particle is thrown with initial speed u at angle ‘θ’, with the horizontal, under gravity. The relation between maximum height ‘h’ and range upon level ground ‘R’ is
Answer» It should be noted that for MAXIMUM range angel is 45°. As per question, Maximum height = H = u²Sin²Ø/2g H = u² sin²45°/2g H = u²/4g -----(1) Range = R = u² Sin2Ø/g R = u² Sin2(45°)/g R = u²/g ------(2) Dividing 1/2, $\dfrac{H}{R}\:=\:\dfrac{{u}^{2}}{4g}\<klux>TIMES</klux>\dfrac{g}{{u}^{2}}$ H/R = 1/4 R = 4H Hence, Range is 4 times the Height.

A particle is thrown with initial speed u at angle ‘θ’, with the horizontal, under gravity. The relation between maximum height ‘h’ and range upon level ground ‘R’ is

Answer»

It should be noted that for MAXIMUM range angel is 45°.

As per question,

Maximum height = H = u²Sin²Ø/2g

H = u² sin²45°/2g

H = u²/4g -----(1)

Range = R = u² Sin2Ø/g

R = u² Sin2(45°)/g

R = u²/g ------(2)

Dividing 1/2,

$\dfrac{H}{R}\:=\:\dfrac{{u}^{2}}{4g}\<klux>TIMES</klux>\dfrac{g}{{u}^{2}}$

H/R = 1/4

R = 4H

Hence,

Range is 4 times the Height.

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A particle is thrown with initial speed u at angle ‘θ’, with the horizontal, under gravity. The relation between maximum height ‘h’ and range upon level ground ‘R’ is

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