a+particle+moves+along+a+circle+of+radius+(20/π)+with+constant+tangen

1.	a+particle+moves+along+a+circle+of+radius+(20/π)+with+constant+tangential+acceleration+.+If+the+velocity+of+the+particle+is+80+m/s+at+the+end+of+the+second+revolution+after+motion+has+began.+What+is+the+tangential+acceleration?
Answer» A particle is moving along a circle of radius 20/\pi20/π with constant tangential acceleration. The velocity of the particle is 80m/s at the end of 2nd revolution after MOTION has BEGAN. Then the tangential acceleration is ANSWER R=\dfrac{20}{\pi}r= π 20 In two revolution , DISTANCE is s=2\times 2\pi r=80ms=2×2πr=80m Now, v^2=2asv 2 =2as for zero INITIAL speed. \implies a=\dfrac{v^2}{2s}=\dfrac{80\times 80}{2\times 80}⟹a= 2s v 2 = 2×80 80×80 \implies a=40m/s^2⟹a=40m/s 2 Explanation:hi

a+particle+moves+along+a+circle+of+radius+(20/π)+with+constant+tangential+acceleration+.+If+the+velocity+of+the+particle+is+80+m/s+at+the+end+of+the+second+revolution+after+motion+has+began.+What+is+the+tangential+acceleration?

Answer»

A particle is moving along a circle of radius 20/\pi20/π with constant tangential acceleration. The velocity of the particle is 80m/s at the end of 2nd revolution after MOTION has BEGAN. Then the tangential acceleration is

ANSWER

R=\dfrac{20}{\pi}r=

In two revolution , DISTANCE is s=2\times 2\pi r=80ms=2×2πr=80m

Now, v^2=2asv

=2as for zero INITIAL speed.

\implies a=\dfrac{v^2}{2s}=\dfrac{80\times 80}{2\times 80}⟹a=

2×80

80×80

\implies a=40m/s^2⟹a=40m/s

Explanation:hi

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