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A particle moves in a straight line as `s =alpha(t-4)+beta(t-4)^(2)`. Find the initial velocity and acceleration. |
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Answer» `s=alpha(t-4)+beta(t-4)^(2)` `=alpha(t-4)+beta(t^(2)-8t+16)` `v=(ds)/(dt)=alpha(1-0)+beta(2t-8)` `a=(dv)/(dt)=beta(2.1)=2beta` At `t=0, v=alpha-8beta` `a=2beta` |
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