1.

A particle moves in east with velocity of 15 m/s for 2 sec. then moves northward with 5 m/s for 8 sec,then average velocity of the particle is-

Answer»

distance travelled in east=15*2=30m

distance travelled in north=5*8=40m

since east and north are perpendicular to each other.

So, displacement=sq. root of [(30)^2+(40)^2]=50m

average velocity=dispacement/total time taken=50/(8+2)=5m/s



Discussion

No Comment Found

Related InterviewSolutions