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A particle moves in east with velocity of 15 m/s for 2 sec. then moves northward with 5 m/s for 8 sec,then average velocity of the particle is- |
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Answer» distance travelled in east=15*2=30m distance travelled in north=5*8=40m since east and north are perpendicular to each other. So, displacement=sq. root of [(30)^2+(40)^2]=50m average velocity=dispacement/total time taken=50/(8+2)=5m/s |
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