1.

A particle moving in a straight in a straight line has velocity and displacement equation as `v = 4 sqrt(1 + s)`, where `v` is in m/s and s is in m. The initial velocity of the particle is:A. 4 m/sB. 16 m/sC. 2 m/sD. zero

Answer» Correct Answer - A
`v = 4 sqrt(1 + s)`
`v^(2) = 16 + 16s`
`v^(2) - 16 = 16s`
`v^(2) - (4)^(2) = 2 (8) s`
`:.` Initial velcoity `= 4 m//s`


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