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A particle moving in a straight in a straight line has velocity and displacement equation as `v = 4 sqrt(1 + s)`, where `v` is in m/s and s is in m. The initial velocity of the particle is:A. 4 m/sB. 16 m/sC. 2 m/sD. zero |
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Answer» Correct Answer - A `v = 4 sqrt(1 + s)` `v^(2) = 16 + 16s` `v^(2) - 16 = 16s` `v^(2) - (4)^(2) = 2 (8) s` `:.` Initial velcoity `= 4 m//s` |
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