A particle of mass 0.01 kg executing shm has 0.04. If the frequency of

1.	A particle of mass 0.01 kg executing shm has 0.04. If the frequency of vibration is 32hz;find its angular velocity,maximum velocity and energy.
Answer» Hey dear, You didn't give the graph. I'll add it with an IMAGE attachment. ◆ Answer- T = 0.3142 s ◆ Solution- # Given- m = 0.01 kg # Solution- We are given with graph if force vs DISPLACEMENT. Force CONSTANT is calculated by slope of graph - k = F / x k = [8 - (-8)] / [2 - (-2)] k = 16 / 4 = 4 N/m Angular velocity is given by - ω = √(k/m) ω = √(4/0.01) ω = 20 m/s Time PERIOD of SHM - T = 2π / ω T = 2×3.142 / 20 T = 0.3142 s Therefore, time period of SHM is 0.3142 s. Hope this helps you...

A particle of mass 0.01 kg executing shm has 0.04. If the frequency of vibration is 32hz;find its angular velocity,maximum velocity and energy.

Answer»

Hey dear,

You didn't give the graph. I'll add it with an IMAGE attachment.

◆ Answer-

T = 0.3142 s

◆ Solution-

# Given-

m = 0.01 kg

# Solution-

We are given with graph if force vs DISPLACEMENT. Force CONSTANT is calculated by slope of graph -

k = F / x

k = [8 - (-8)] / [2 - (-2)]

k = 16 / 4 = 4 N/m

Angular velocity is given by -

ω = √(k/m)

ω = √(4/0.01)

ω = 20 m/s

Time PERIOD of SHM -

T = 2π / ω

T = 2×3.142 / 20

T = 0.3142 s

Therefore, time period of SHM is 0.3142 s.

Hope this helps you...

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A particle of mass 0.01 kg executing shm has 0.04. If the frequency of vibration is 32hz;find its angular velocity,maximum velocity and energy.

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