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A particle of mass 2 kg is dropped from a height of 20m and rises to a height of 5m. Calculate thechange in momentum between before and afterhitting the ground(1) 30 kg m/s(2) Zero(3) 10 kg m/s(4) 60 kg m/s |
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Answer» 4-60 kg m/sExplanation:VELOCITY=(2×HEIGHT /g) ^1/2where, g=acceleration due to gravity=10Initial velocity=(2×INITIAL height /g) ^1/2 =20m/sFinal velocity=(2×final height /g) ^1/2 - 10m/s('-' is used because direction is opposite to initial direction) Change in momentum=mass×change in velocity=2×[20-(-10)]=60 kg m/s |
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