A particle of mass 2 m is projected at an angle of 45Â° with horizon

1.	A particle of mass 2 m is projected at an angle of 45Â° with horizontal with a velocity of20/2 m/s. After 1 s explosion takes place and the particle is broken into two equal pieces. As aresult of explosion one part comes to rest. Find the maximum height attained by the other part.Take 2810m/s
Answer» The answer for this question is35 m. Initially the velocity is 20root(2)ms-1& the angle is 45. Vertical component of velocity = 20ms-1 After 1 s, It will cover a distance of s = ut+1/2at2= (20)(1)+1/2(-10)(1)2= 20 - 5 = 15m and its vertical velocity comp. will be reduced to 10ms-1. Soon After it s mass gets reduced to m from 2m due to reaking so according to the law of conser. of center of mass, it velocitys vertical comp. will be doubled. =10ms-1.*2 =20ms-1 Now for coming to rest it has to cover diatnce v2= u2-2gs=> 400/20=s = 20m So the total height achieved by the the ball is 20+15 = 35 m

A particle of mass 2 m is projected at an angle of 45Â° with horizontal with a velocity of20/2 m/s. After 1 s explosion takes place and the particle is broken into two equal pieces. As aresult of explosion one part comes to rest. Find the maximum height attained by the other part.Take 2810m/s

Answer»

The answer for this question is35 m.

Initially the velocity is 20root(2)ms-1& the angle is 45. Vertical component of velocity = 20ms-1

After 1 s, It will cover a distance of s = ut+1/2at2= (20)(1)+1/2(-10)(1)2= 20 - 5 = 15m and its vertical velocity comp. will be reduced to 10ms-1.

Soon After it s mass gets reduced to m from 2m due to reaking so according to the law of conser. of center of mass, it velocitys vertical comp. will be doubled. =10ms-1.*2 =20ms-1

Now for coming to rest it has to cover diatnce v2= u2-2gs=> 400/20=s = 20m

So the total height achieved by the the ball is 20+15 = 35 m

Discussion

No Comment Found

Related InterviewSolutions

7. A body has a weight 50 N in air. Afterimmersing completely in liquid its weight is20 N. Then, the buoyant force on the bodywill be
Name the particulate which causes the disease mentioned below:(a)minamata (b)silicosis.
- Where does a body weight more at the surface of the carth or in a mine?
DelyAbody79entire chainthe ch.57. A body of mass 50gm collides elastically with anotherbody of mass 30 gm at rest. Then the percentage lossof the velocity of the colliding body during collision is1) 25% 2) 75% 3) 50% 4) 67%3) 120380.beide
What will be the acceleration of a body of mass5 kg if a force of 200 N is applied on it?
Rig. 5.168.13 Two bodles of masses 10 kg and 20 kg respectively kept on a smooth, hortzontalsurface are tied to the ends of a light string a horizontal force F 600 Nsapplied to lu A (t) B along the direction of string. What is the tension in thestring in each case
culate the gravitational force befween two protons kept at a distance67 x 10-27 kg. (1 femtometre = 10-15 m)
15. A uniform chain of length 2 m is kept on atable such that a length of 60 cm hangs freelyfrom the edge of the table. The total mass ofthe chain is 4 kg. What is the work done inpulling the entire chain onto the table ?(g = 10 m/s)1) 7.2J273.63) 120J4) 1200
Two block of mass 3 kg and 6 kg respectively are placed on a smooth 1.0 m/shorizontal surface. They are connected by a light spring of force 3 kgconstant k 200 N/m. Initially the spring is unstretched. The indicatedzmvelocities are imparted to the blocks. The maximum extension of thespring will be:A30 cm(C) 20 cm2.0 mls(B) 25 cm(D) 15 cm
88. A piece of stone is thrown vertically upwards. It reaches the maximum height in 3 seconds. If the accelerationof the stone be 9.8 m/s directed towards the ground, calculate the initial velocity of the stone with which itis thrown upwards.