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A particle of mass m and charge q is releasedfrom rest in an electric field E. Then the K.E.after time t will be : |
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Answer» force=qE,impulse=qEt=momentum=p, k.e.=p2/2mOr 1) qE + mg = maa = qE/m + g 2) v = 0 + at v = (qE/m + g)t
3) K.E =1/2mv^2 = 1/2m [(qE/m + g)t]^2 Joule |
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