1.

A particle of mass m and charge q is releasedfrom rest in an electric field E. Then the K.E.after time t will be :

Answer»

force=qE,impulse=qEt=momentum=p, k.e.=p2/2mOr

1) qE + mg = maa = qE/m + g

2) v = 0 + at

v = (qE/m + g)t

3) K.E =1/2mv^2

= 1/2m [(qE/m + g)t]^2 Joule



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