A particle of mass `M` at rest dacays into two particle of masses `m_(1)` and `m_(2) `having non zero velocity . The radio of the de Broglie wavelength . The ratio of the de Broglie wavelengtgh of the particle `lambda , _(1) // lambda_(2)` isA. `m_(1)//m_(2)`B. `m_(2)//m_(1)`C. `1.0`D. ` sqrt(m_(1))//sqrt(m_(2))`

A particle of mass `M` at rest dacays into two particle of masses `m_(

1.	A particle of mass `M` at rest dacays into two particle of masses `m_(1)` and `m_(2) `having non zero velocity . The radio of the de Broglie wavelength . The ratio of the de Broglie wavelengtgh of the particle `lambda , _(1) // lambda_(2)` isA. `m_(1)//m_(2)`B. `m_(2)//m_(1)`C. `1.0`D. ` sqrt(m_(1))//sqrt(m_(2))`
Answer» Correct Answer - C Appling conservation of linear momentum, intial momentum = final momentum `0 = M_(1) NU_(1) - M_(2)NU_(2)rArr M_(1) NU_(1) M_(2)NU_(2)` = `Now , (lambda_(1))/(lambda_(2)) = (h// M_(1) NU_(1))/((h// M_(2) NU_(2)) = 1`

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