1.

. A particle of mass M is fired with speed u makingangle θ with the horizontal. Its potential energy atthe highest point is-

Answer»

Final potential energy = MgH

where H is maximum height of projectile.

H = u^2 sin^2 theta/2g

So, Final potential energyPEf = -Mgu^2 sin^2 theta/2g = - Mu^2 sin^2 theta/2



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