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A particle of mass `m` is moving in a plane along a circular path of radius `r`. Its angular momentum about the axis of rotation is `L`. The centripetal force acting on the particle is.A. `(L^(2))/(mr)`B. `(L^(2)m)/r`C. `(L^(2))/(mr^(2))`D. `(L^(2))/(mr^(2))` |
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Answer» Correct Answer - D `L=mvrrArrv=L/(mr)` centripetal force `F=(mv^(2))/r=(L^(2))/(mr^(3))` |
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