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A particle of mass m is projected with speed u at an angle `theta` with the horizontal. Find the torque of the weight of the particle about the point of projection when the particle is at the highest point.A. `(mgu^(2)sin 2 theta)/2`B. `mgu^(2)sin 2 theta`C. `(mgu^(2)sin theta)/2`D. `1/2 m u^(2)sin 2 theta` |
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Answer» Correct Answer - D `vec(tau)=[R/2hati+Hhatj]xxmghatj` |
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