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A particle oscillation is given by `(f_(0)) = kpl^(2)` with for constant `k` and an amplitude A The maximum velocity during the oscillation a preperitiaonal to :A. `A`B. `A^(2)`C. `A^(3//2)`D. none of these |
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Answer» Correct Answer - C Let at any time displacement is `y` and velocity is `s` since total energy can be the maximum `PE` we get `(1)/(2) mv^(2) + ky^(3) = kA^(3) rArr = sqrt((2k(A^(2)- y^(3)))/(m))` Velocity maximum is therefore `(at y = 0)` `v_(max) = sqrt((2kA^(2))/(m)) rArr v_(max) prop A^(1//2)` |
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