1.

The potential energy of a particle of mass `1kg` in motion along the x- axis is given by: `U = 4(1 - cos 2x)`, where `x` in metres. The period of small oscillation (in sec) isA. `2pi`B. `pi`C. pi//2`D. `pi//4`

Answer» Correct Answer - C
`F = -(dU)/(dx) = - 8 sin 2s`
For small oscilation
`S` in `2x = 2s`
i.e. `a = - 16x`
Since `a = 1x`
the oscilation are `SH` in rature
`T = 2pi sqrt(|(x)/(a)|) = 2pi sqrt((1)/(16)) = (pi)/(2) sec`


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