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The potential energy of a particle of mass `1kg` in motion along the x- axis is given by: `U = 4(1 - cos 2x)`, where `x` in metres. The period of small oscillation (in sec) isA. `2pi`B. `pi`C. pi//2`D. `pi//4` |
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Answer» Correct Answer - C `F = -(dU)/(dx) = - 8 sin 2s` For small oscilation `S` in `2x = 2s` i.e. `a = - 16x` Since `a = 1x` the oscilation are `SH` in rature `T = 2pi sqrt(|(x)/(a)|) = 2pi sqrt((1)/(16)) = (pi)/(2) sec` |
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