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A mass `M` is suspended from a spring of negiliglible mass the spring is pulled a little and then released so that the mass executes simple harmonic oscillation with a time period `T` If the mass is increases by `m` the time period because `((5)/(4)T)`,The ratio of `(m)/(M)` isA. `9//16`B. `25//16`C. `4//5`D. `5//4` |
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Answer» Correct Answer - A `T = 2pi sqrt((m)/(k)) rArr m prop T^(2) rArr (m_(2))/(m_(1)) = (T_(2)^(2))/(T_(1)^(2))` ` rArr (M +m)/(M) = = (((5)/(4)T)/(T))^(2) rArr (m)/(M) = (9)/(16)` |
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