1.

Two simple pendulum of length `1m` and `16m` respectively are both given small displacement in the same direction of the same instant. They will be phase after one shorter pendulum has complated a oscillations. The value of `n` isA. `1//3`B. `2//3`C. `1`D. `4//3`

Answer» Correct Answer - D
`T_(1) = 2 pi sqrt((1)/(g)) , T_(2) = 2piu sqrt((16)/(g)) = 4T_(1)`
at any time `t` phase of pendulums are
`phi_(1) = omega_(1)t = (2pi)/(T_(1)) t, phi_(2) = omega_(2)t = (2pi)/(T_(2)) t`
First pendulum is faster both will be in same phase again when faster pendulum completated one oscillation more than slower pendulum
`rArr (2pi)/(T_(1)) t - (2pi)/(4T_(1)) t = 2 pi rArr t = (4T_(1))/(3)`
No of oscillation completed by shorter pendulum in time `t`
`n = (t)/(T_(1)) = (4)/(3)`


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