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A particle performing uniform circular motion gas angular momentum `L`. If its angular frequency is double and its kinetic energy halved, then the new angular momentum is :A. 2LB. 4LC. L/2D. L/4 |
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Answer» Correct Answer - D Kinetic energy =`1/2 L omega` `(K_(1))/(K_(2))=(L_(1)omega_(1))/(L_(2)omega_(2))` `L_(2)=L//4` |
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