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A particle starting from rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be. A. 110 m/sB. 55 m/sC. 550 m/sD. 660 m/s |
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Answer» Correct Answer - B The velocity increase upto `t = 11s` as acceleration remains positive (although it decrease). `:.` Max. velocity = Area under `v - t` graph `= (1)/(2) xx 11 xx 10 = 55 m//s` |
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