InterviewSolution
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InterviewSolution
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A particle starts from rest with a constant aceleration. At a time t secon, the speed is found tobe 100 m/s and one second later the speed becomes 150 m/s. Find a. the acceleratiuon and b. the distance travelled during the `(t+1)^th` second. |
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Answer» a. Velocity at time t is `100 m/s=a.(t second)`…………i and velocity at time (t+1) second `150 m/s=a.(t+1) ………..2 Subtracting 1 from 2, `a=50 m/s^2` b. consider the interval t second to `(t+1)` second, time elapsed = 1s initial velocity = 100 m/s fiN/Al velocity = 150 m/s Thus `(150 m/s)^2=(100 m/s)^2+2(50+m/s^2)x` or, `x=125m`. |
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