1.

A particle starts SHM from the mean position. Itsamplitude is a and total energy E. At one instant, itskinetic energy is 3E/4 Its displacement at that instant is(a) 1/V2(c) Q(b) a/2(d) a//3/3/2

Answer»

The equation of the simple harmonic motion is y = A sinωt with usual notations.

The total energy is (½) m ω2a2and the kinetic energy is (½)m ω2(a2–y2).

Therefore we have (½) m ω2a2= E and(½)m ω2( a2–y2) = 3E/4.

Dividing the second equation by the first, 1 – y2/a2= ¾, from which y = a/2.



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