1.

A particle travels 10 m in first 5 sec and 10 m in next3 sec. Assuming constant acceleration, what is thedistance travelled in next 2 sec?(a) 8.3 m(c) 10.3 mm(b) 9.3 m(d) of above

Answer»

Let assume initial velocity is u and constant acceleration a.

using s=ut+.5 a t^2

For first 5 second

10=5 u +.5x a x 25..........(1)

for next 3 seconds t=8 and s=20

20=8 u+.5xax64...........(2)

Solving 1 and 2

a=1/3 and u=7/6

Now for next 2 seconds t=10 and s'

S'=10x7/6 +.5x(1/3) 100

S'=170/6

Now distance travelled in 2 sec=(170/6)-20=50/6 meter

thnk u sir, it helped me a lot


Discussion

No Comment Found

Related InterviewSolutions