A Person Invests Money In Three Different Schemes For 6 Years, 10 Yea

1.	A Person Invests Money In Three Different Schemes For 6 Years, 10 Years And 12 Years At 10 %, 12 %, And 15 %. Simple Interest Respectively. At The Completion Of Each Scheme, He Gets The Same Interest. The Ratio Of His Investments Is?
Answer» LET the REQUIRED ratio be x: 1: y. Then S.I on Rs x for 6 YEARS at 10% p.a = S.I on re.1 10 years at 12 %p.a X × 10/100 × 6 = 1 × 12/100 × 10 => X = 120/60 =2 S.I on Re.1 for 10 years at 12 % p.a = S. I on Rs. Y for 12 years at 15 % p.a Therefore, (1 x 12/100 x 10) = (y x 15/100 x 12) => y = 120/180 = 2/3 Required ratio = 2 : 1 = 2/3 = 6 : 3 : 2. Let the required ratio be x: 1: y. Then S.I on Rs x for 6 years at 10% p.a = S.I on re.1 10 years at 12 %p.a X × 10/100 × 6 = 1 × 12/100 × 10 => X = 120/60 =2 S.I on Re.1 for 10 years at 12 % p.a = S. I on Rs. Y for 12 years at 15 % p.a Therefore, (1 x 12/100 x 10) = (y x 15/100 x 12) => y = 120/180 = 2/3 Required ratio = 2 : 1 = 2/3 = 6 : 3 : 2.

A Person Invests Money In Three Different Schemes For 6 Years, 10 Years And 12 Years At 10 %, 12 %, And 15 %. Simple Interest Respectively. At The Completion Of Each Scheme, He Gets The Same Interest. The Ratio Of His Investments Is?

Answer»

LET the REQUIRED ratio be x: 1: y.

Then S.I on Rs x for 6 YEARS at 10% p.a = S.I on re.1 10 years at 12 %p.a

X × 10/100 × 6 = 1 × 12/100 × 10

=> X = 120/60 =2

S.I on Re.1 for 10 years at 12 % p.a = S. I on Rs. Y for 12 years at 15 % p.a

Therefore, (1 x 12/100 x 10) = (y x 15/100 x 12)

=> y = 120/180 = 2/3

Required ratio = 2 : 1 = 2/3 = 6 : 3 : 2.

Let the required ratio be x: 1: y.

Then S.I on Rs x for 6 years at 10% p.a = S.I on re.1 10 years at 12 %p.a

X × 10/100 × 6 = 1 × 12/100 × 10

=> X = 120/60 =2

S.I on Re.1 for 10 years at 12 % p.a = S. I on Rs. Y for 12 years at 15 % p.a

Therefore, (1 x 12/100 x 10) = (y x 15/100 x 12)

=> y = 120/180 = 2/3

Required ratio = 2 : 1 = 2/3 = 6 : 3 : 2.

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