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A person is using a concave lens of power -1.5D for distant vision. How has far point of her eye shifted ?? |
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Answer» Answer: Unknown. Explanation: P = 1/FGiven : P = - 1.5 D → - 1.5 D = 1/f → f = 1/(- 1.5) → f = - 2/3 or - 0.67 m Or in other units, focal length → - 0.67 × 100 = - 67 cm Mirror Formula→ 1/f = 1/v - 1/u → 1/(- 67) = 1/v - 1/u Since the question doesn't mention where the object has placed hence VALUE of v will be in terms of u → - 1/67 + 1/u = 1/v → (67 - u)/67u = 1/v → v = 67u/(67 - u) Hence far point is surely SHIFTED from ∞. |
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