1.

A person of mass 50 kg stands on a weighing scale on a lift . If the lift is descending with a downward acceleration of `9ms^(-2)` what would be the reading of the weighing scale? `(g =10ms^(-2)) ` .

Answer» Reading of weighing scale =
apparent wt. of person ` = R = m (g-a) = 50 (10 - 9) = 50 N = 5 kg ` .


Discussion

No Comment Found

Related InterviewSolutions