A person of mass M kg is standing on a lift. If the lift moves vertica – InterviewSolution

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1.	A person of mass M kg is standing on a lift. If the lift moves vertically upwards according to given v-t graph then find out the weight of the man at the following instants :(g=10m/s). Find his apparent weight at t=12 seconds.
Answer» From t=10 sec to t=12 sec s = area under v-t graph = 1/2 * 4 * 20 = 40 mt also s = ut + 1/2 at^2 from solving this you will get a = -5 m/s^2 So the lift is descending with a acc. = 5 m/s^2 So the forces on the person are g downwards ( w.r.t ground ) and a upwards ( w.r.t ground ) so net force on person w.r.t ground is g - a = 10 - 5 = 5 m/s^2 Hence the apparent weight is W = m * a = M * 5 = 5M

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